Question

The base of an isosceles triangle is 24 cm.and its area is 60 square cm.Find its perimeter

Answer 1

let equal side be x

s=24+2*x/(2)

s=x+12

area=square root(x+12)(x-12)12*12

60=12 square root(x+12)(x-12)

x=13

perimeter=13+13+24

=50