The base of an isosceles triangle is 24 cm nd area is 192cm^2 find perimeter
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area of isosceles triangle = 1/2×b×h
192=1/2×24×h
h=192×2/24
h=16 cm
two right angle triangle (hyp)^2=12×12+16×16
(hyp)^2=400
(hyp)=√400
(hyp)=20cm
perimeter of isosceles triangle=a+b+c
=20+20+24
=64cm
192=1/2×24×h
h=192×2/24
h=16 cm
two right angle triangle (hyp)^2=12×12+16×16
(hyp)^2=400
(hyp)=√400
(hyp)=20cm
perimeter of isosceles triangle=a+b+c
=20+20+24
=64cm
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