The base of an isosceles triangle is 24cm, if its perimeter is 5 dm, then find its area?
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base = 24cm
the two sides of isosceles triangle will be equal
therefore, let each side be xcm
perimeter of triangle = sum of all sides
50 =24+x+x
50-24=2x
26=2x
x=13cm
s=13+13+24/2
=25
by herons formula
area of triangle =√25(25-13)(25-13)(25-24)
=√25(12)(12)(1)
=√25*144
=60cm^2
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