The base of an isosceles triangle is 24cm if its perimeter is 5cm then find its area
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peremiter = 2a + b
5 =2a+ 24 ( let base be 24 cm)
5-24=2a
-19= 2a
a=(-19/2)
a=19/2 cm
area= b×h/2
area=24×19/2/2
area=24×19/2×1/2
area=24×19/4
area=6×19
area=114cm^(2)
If you like it so plz mark it brainliest
5 =2a+ 24 ( let base be 24 cm)
5-24=2a
-19= 2a
a=(-19/2)
a=19/2 cm
area= b×h/2
area=24×19/2/2
area=24×19/2×1/2
area=24×19/4
area=6×19
area=114cm^(2)
If you like it so plz mark it brainliest
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