Question

the base of an isosceles triangle is 4/3 cm. The perimeter of the triangle is 4 2/15 cm. What is the length of either of the remaining equal sides?​

Answer 1

Answer:

HEY MATE HERE IS YOUR ANSWER

Answer 2

Answer:

Let 'x' be the equal remaining sides of a triangle.

So, its length =

$(x + x + \frac{4}{3} ) \: cm$

Perimeter of a triangle =

$4 \times \frac{2}{15} cm$

$= \frac{62}{15} cm$

x + x + base of an isosceles triangle = perimeter

$= > x + x + \frac{4}{3} = \frac{62}{15} cm$

$= > 2x + \frac{4}{3} = \frac{62}{15} cm$

$= > 2x = \frac{62}{15} - \frac{4}{3}$

$= > 2x = \frac{62 - 20}{15}$

$= > 2x = \frac{42}{15}$

$= > x = \frac{42}{15} \times \frac{1}{2}$

$= > x = \frac{42}{30}$

$= > x = \frac{7}{5}$

$= > x = 1 \ \frac{2}{5} cm$

∴ The length of the remaining equal sides =

$1 \frac{2}{5} cm$