Math, asked by abhishekpal73, 1 year ago

the base of an isosceles triangle is 4/3 cm.the perimeter of the triangle is 62/15 cm. what is the length of either of remaining equal sides​

Answers

Answered by Anonymous
4

Answer:

1.4cm

Step-by-step explanation:

so first convert all fractions to decimals for simplification or use fraction and turn to decimals at last

so

let one of equal sides be x

2x+4/3=62/15

(given)

2 (x+2/3)=2×31/15

(cancel 2 from both sides)

x+2/3=31/15

x=(31/15)-(2/3)=31-10/15=21/15

x =7/5 or 1.4cm

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Answered by rajsingh24
6

Step-by-step explanation:

base=4/3

perimeter =s1+s2+s3

62/15=x+x+4/3

62/15=2x+4/3

62/15-4/3=2x

(62-20)15=2x

42/15=2x

42/15×1/2=x

21/15=x

7/5=x.

length of either of remaining equal sides=7/5cm.

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