the base of an isosceles triangle is 4/3 cm.the perimeter of the triangle is 62/15 cm. what is the length of either of remaining equal sides
Answers
Answered by
4
Answer:
1.4cm
Step-by-step explanation:
so first convert all fractions to decimals for simplification or use fraction and turn to decimals at last
so
let one of equal sides be x
2x+4/3=62/15
(given)
2 (x+2/3)=2×31/15
(cancel 2 from both sides)
x+2/3=31/15
x=(31/15)-(2/3)=31-10/15=21/15
x =7/5 or 1.4cm
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Answered by
6
Step-by-step explanation:
base=4/3
perimeter =s1+s2+s3
62/15=x+x+4/3
62/15=2x+4/3
62/15-4/3=2x
(62-20)15=2x
42/15=2x
42/15×1/2=x
21/15=x
7/5=x.
length of either of remaining equal sides=7/5cm.
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