Question

The base of an isosceles triangle is 4/3 cm . The perimeter of the triangle is 62/15 . What is the length of either of the remaining equal sides?
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Answer 1

Answer:

let the equal sides be x

so,x+x+4/3=62/15

2x=62/15-4/3

x=42/15×2

x=21/15 cm

Answer 2

Answer:

7/5 cm

Step-by-step explanation:

Base of isosceles triangle = 4/3 cm

Perimeter of triangle = 62/15 cm

Let the length of equal sides of triangle be x.

According to the question,

4/3 + x + x = 62/15 cm

⇒ 2x = (62/15 – 4/3) cm

⇒ 2x = (62 – 20)/15 cm

⇒ 2x = 42/15 cm

⇒ x = (42/30) × (½)

⇒ x = 42/30 cm

⇒ x = 7/5 cm

The length of either of the remaining equal sides are 7/5 cm.