Question

the base of an isosceles triangle is 4/3 cm. The perimeter of a triangle is 4*2/15cm. What is the length of either of the remaining equal sides ​

Answer 1

Answer:

Let △ABC be an isosceles triangle

Base=BC=$\frac{4}{3} cm {}^{3}$

Let AB=X

So BC=x [ Two sides of isosceles triangle are equal]

Given:

Perimeter =4*2/15

=[4×15+2]/15=[60+2]/15=62/15 cm

Also, Perimeter = Sum of sides

=62/15=AB+BC+AC

=62/15=x+x+4/3

=62/15=2x+4/3

=2x=42/15

=x=42/15×1/2

=x=21/15

=x=7/5 cm

∴ length of remaining two sides =7/5 cm

Answer = 7/5 cm