Question

the base of an isosceles triangle is 4/3 cm . the perimeter of triangle is 62/ 15 cm what is the length of the either side of the remaining equal sides
hint= let the equal side= x
perimeter of triangle=(x+x+4/3)cm
62/15cm =(2x+4/3)cm​

Answer 1

Step-by-step explanation:

Base=4/3cm

Let the equal sides be x.

Perimeter=S1+S2+S3

62/15=x+x+4/3

62/15=2x+4/3

62/15-4/3=2x

(62-20)/15=2x

42/15/2=x

42/15×1/2=x

21/15=x

7/5=x

Thus,

Two equal sides = x = 7/5cm

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Answer 2

Answer:

Length of the either equal sides ( taken as x )is 7/5 cm.

Step-by-step explanation:

Perimeter = 62/15

=>x +x +4/3 = 62/15

=>2x =62/15 - 4/3 = (62 - 20) / 15 = 42 / 15

=>2x = 42/15

=>x = 42/30

=>x = 7/5