Question

The base of an isosceles triangle is 4/3 cm. The perimeter of the triangle is 4 2/5 cm.
What is the length of either of the remaining equal sides?

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Answer 1

Answer:

Length of equal sides =  92/15 cm

Step-by-step explanation:

Let one of the equal sides be x

∴ Perimeter = 4 2/5

= 22/5 cm

Base of the Triangle = 4/3 cm

Perimeter of Triangle = x + x + 4/3

2x + 4/3 = 22/5

2x = 22/5 - 4/3

2x = 66 - 20/15

2x = 46/15

x = 46/15/2

∴  length of equal sides =  92/15 cm

x = 92/15 cm

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Answer 2

✪AnSwEr

${\tt{\red{\underline{\large{Given}}}}}$

• Base of isosceles ∆ 4/3cm
• Perimeter of ∆ = 42/5cm

${\sf{\green{\underline{\large{To\:find}}}}}$

• Remaining sides

${\sf{\pink{\underline{\Large{Explanation}}}}}$

Diagram

$\setlength{\unitlength}{5mm}\begin{picture}(5,5)\put(0,0){\line(1,0){8}}\put(0,0){\line(2,1){6}}\put(8,0){\line(-2,3){2}}\end{picture}$

Let the equal sides of isosceles ∆ be x

Then

=>x+x+4/3 = 42/5

=>2x+4/3=42/5

=>2x=42/5 - 4/3

=>2x={66-20}/15

=>2x=46/15

=>x=46/30

=>x=23/15

=>x=23/15

Hence the value of x is 23/15