Math, asked by sanapereira8, 8 months ago

The base of an isosceles triangle is 4/3 cm. The perimeter of the triangle is 62/15 cm. What is the length of either of the remaining sides?

Answers

Answered by abhajaiswal303
2

Answer:

the length of other two remaining sides are 62/15-4/3

62-20/15

42/15

length of each side is 42/15 ×1/2

21/15

Step-by-step explanation:

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Answered by Anonymous
1

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Base=4/3cm

Let the equal sides be x.

Perimeter=S1+S2+S3

  • 62/15=x+x+4/3
  • 62/15=2x+4/3
  • 62/15-4/3=2x
  • (62-20)/15=2x
  • 42/15/2=x
  • 42/15×1/2=x
  • 21/15=x
  • 7/5=x

Thus,

Two equal sides = x = 7/5cm

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