The base of an isosceles triangle is 4/3 cm. The perimeter of the triangle is 62/15 cm. What is the length of either of the remaining sides?
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Answer:
the length of other two remaining sides are 62/15-4/3
62-20/15
42/15
length of each side is 42/15 ×1/2
21/15
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Base=4/3cm
Let the equal sides be x.
Perimeter=S1+S2+S3
- 62/15=x+x+4/3
- 62/15=2x+4/3
- 62/15-4/3=2x
- (62-20)/15=2x
- 42/15/2=x
- 42/15×1/2=x
- 21/15=x
- 7/5=x
Thus,
Two equal sides = x = 7/5cm
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