Question

The base of an isosceles triangle is 4/3 cm. The perimeter of the triangle is 2/15 cm. What is the length of either of the remaining equal sides?

Answer 1

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Explanation:

Base=4/3cm

Let the equal sides be x.

Perimeter=S1+S2+S3

62/15=x+x+4/3

62/15=2x+4/3

62/15-4/3=2x

(62-20)/15=2x

42/15/2=x

42/15×1/2=x

21/15=x

7/5=x

Thus,

Two equal sides = x = 7/5cm

Answer 2

Base of isosceles triangle = 4/3 cm

Perimeter of triangle = 2/15 cm

Let the length of equal sides of triangle be x.

According to the question,

4/3 + x + x = 2/15 cm

⇒ 2x = (2/15 – 4/3) cm

⇒ 2x = (2 – 20)/15 cm

⇒ 2x = 18/15 cm

⇒ x = (18/15) × (½)

⇒ x = 18/30 cm

⇒ x = 9/15 cm

The length of either of the remaining equal sides are 9/15 cm.