Question

the base of an isosceles triangle is 4/3 cm.the perimeter of the triangle is 4 integer 2/15cm.what is the length of either of the remaining equal sides?

no spam pls..​

Answer 1

• Let the length of equal sides be x cm Perimeter = x cm + x cm + Base = 4 2/15 cm
• 2x + 4/3 = 62/15
• On transposing 4/3 to R.H.S,
• we obtain 2x = 62/15 - 4/3 2x = 62 - 4 x 5/15 = 62 - 20/15 2x = 42/15
• On dividing both sides by 2, we obtain 2x/2 = 42/15 x1/2 x = 7/5 = 1 2/5
• Therefore,

the length of equal sides is 1 2/5 cm.

Answer 2

Answer:

Brother, what's is your real name and where are

you from?

I'm Mian (Army girl) age 16 from Meghalaya.

Brother,can I be your sis ?

Purple you

pls report this after reading brother