Question

the base of an isosceles triangle is 4/3 cm. The perimeter of the triangle is 4 2/15 cm. what is the length of of the remaining equal sides​

Answer 1

Length of equal side = 7/3 cm

Isosceles triangle

base. = 4/3 cm

let equal side be x

perimeter = 4. 2 /15 cm

= 62 / 15 cm

perimeter = 4/3 + 2 x

4/3 + 2x = 62 / 15

2x = 62 / 15 - 4/3

2x. =( 62 - 20) / 15

2x = 42 / 15

2x =. 14 /3

x = 7/3

Answer 2

Base = 4/3

Perimeter = 62/15

$\frac{62}{15} = x + x + \frac{4}{3}$

$\frac{62}{5} = 2x + \frac{4}{3}$

$\frac{62}{15} - \frac{4}{3} = 2x$

$\frac{62 - 20}{15} = 2x$

$\frac{42}{15} = 2x$

$\frac{42}{15} \times \frac{1}{2} = x$

$\frac{21}{15} = x$

$\frac{7}{5} = x \\ = = = =$