Question

the base of an isosceles triangle is 4/3 cm. The perimeter of the triangle is 62/15cm.what is the length of the remaining equal sides?​

Answer 1

Answer:

1 2/5

Step-by-step explanation:

Let the length of equal sides be x cm. Perimeter = x cm + x cm + Base = 4 2/15 cm 2x + 4/3 = 62/15 On transposing 4/3 to R.H.S, we obtain 2x = 62/15 - 4/3 2x = 62 - 4 x 5/15 = 62 - 20/15 2x = 42/15 On dividing both sides by 2, we obtain 2x/2 = 42/15 x1/2 x = 7/5 = 1 2/5 Therefore, the length of equal sides is 1 2/5 c m.

Answer 2

Answer:

let the side be xcm

perimeter of triangle =62/15cm

base of isosceles triangle=4/3cm

then

perimeter of triangle=4/3+x+x

62/15=4/3+2x

62/15-4/3=2x

lcm of 3and 15is 15

62-20/15=2x

42/15=2x

42/30=x

21/15=x

7/5cm=x

the length of the remaining equal side is 7/5cm