Question

the base of an isosceles triangle is 4/3 cm. The perimeter of the triangle is 4 2/3 cm what is the length of either of the remaining equal sides ?


Answer:
Let the length of equal sides of ∆ = x
perimeter of ∆ = sum of the three sides
= ( x + x +4/3 ) cm = ( 2x + 4/3 ) cm
= 2x + 4/3 = 4 2/15
= 2x + 4/3 = 62/15
= 2x = 62/15 - 4/3
= 2x =62- 20/ 15
= 2x = 42/15
= x = 42/ 15 ÷ 2
= x = 42/16 × 1/2
= x = 21 / 15 = 7/5
= x = 7/5 ( divide 7/5 = 1 2/ 5)

thus, the required length of each of equal sides = 1 2/5
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Answer 1

Step-by-step explanation:

Here is your Answer..

Perimeter of triangle = Sum of all sides

x + x + 4/3 = 4 2/3

x + x = 14/3 - 4/3

x + x = 10/3

x + x = 3 1/3

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