Question

The base of an isosceles triangle is 4/3 cm. the perimeter of the triangle is 4 2/15 cm. what is
the length of either of the Remaining equal sides ?
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Answer 1

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Answer 2

Answer :

• 1 ⅖ is the length of either of the remaining equal sides

Given :

• The base of an iscoscles triangle is 4/3 cm
• The perimeter of the triangle is 4 2/15 cm

To find :

• The length of either of the remaining equal sides

Solution :

• Let the triangle ABC be an iscoscles triangle

• Base will be bc = 4/3cm

• Let the AB be x
• Let the AC be x

Because two sides of isosceles triangle are equal

Given,

• Perimeter is 4 2/15 cm

➟ Perimeter = 4 2/15

➟ 4 × 15 + 2 / 15

➟ 60 + 2 / 15

➟ 62/15

Perimeter is 62/15

Now,

• Perimeter = Sum of sides

➟ 62/15 = AB + AC + BC

➟ 62/15 = x + x + 4/3

➟ 62/15 = 2x + 4/3

➟ 2x + 4/3 = 62/15

➟ 2x = 62/15 - 4/3

➟ 2x = 62 - 4 × 5 / 15

➟ 2x = 62 - 20 / 15

➟ 2x = 42/15

➟ x = 42/15 × 1/2

➟ x = 21/15

➟ x = 7/5

➟ x = 1 ⅖

Hence,1 ⅖ is the length of either of the remaining equal sides