Question

the base of an isosceles triangle is 4/3 cm.the perimeter of the triangle is 4 2/15 cm.What is the length of either of the remaining equal sides?

Answer 1

$\frac{Perimeter-Base}{2}$ = Length of one among equal sides. 

$\frac{(4\frac{2}{15} - \frac{4}{3})}{2}$
$= \frac{(\frac{62}{15} - \frac{4}{3})}{2}$
$= \frac{(\frac{62}{15} - \frac{20}{15})}{2}$
$= \frac{(\frac{62 - 20}{15})}{2}$
$= \frac{(\frac{42}{15})}{2}$
$= \frac{42}{15}$ ÷ 2
$= \frac{42}{15} * \frac{1}{2}$
$= \frac{42}{30} = \frac{7}{5} = 1\frac{2}{5} = 1.4 cm$

Hope this will be helpful.