The base of an isosceles triangle is 4/3cm.The perimeter of the triangle is 4 2/5cm,what is length of either of remaining equal sides?
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Answered by
1
Answer:
base = 4/3cm
perimeter = 22/5 cm
2a + b = 22/5
where a is side and b is base
2a = 22/5 - b
2a = 66 - 20/15
2a = 46/15
a = 23/15
Answered by
3
Answer:
Let the remaining sides of an isoscles triangle be x cm.
according to question,
x + x + 4/3 = 4 2/ 15 cm
Or, 3x + 3x +4 /3 = 62/15
Or, 45x + 45x + 60 = 186
Or, 90x = 126
Or, x = 126/90
x = 7/15
hence x = 1 2/15
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