Question

the base of an isosceles triangle is 4/3cm . the perimeter of triangle is 62/15cm what is length of either of the remaining equal sidesno​

Answer 1

Answer:

7/5

Step-by-step explanation:

perimeter of isosceles triangle =62/15

base of triangle = 4/3

let one of the two equal side= x

ATQ-

Perimeter of isosceles triangle =base + sum of two equal sides

62/15 = 4/3+ x+ x

62/15 = 4/3 + 2x

62/15 - 4/3 = 2x

(62-20)/15 = 2x

42/15 =2x

21/15= x

7/5=x

ans=7/5

Answer 2

Answer:

5/3

Step-by-step explanation:

WE KNOW THAT REMAINING TWO SIDES ARE EQUAL

THEREFORE LET TAKE THE BOTH SIDES AS X

THOUGH WE GOT THE SIDES- X,X,4/3CM

NOW PERIMETER OF TRIANGLE =SUM OF ALL SIDES

THEN GIVEN PERIMETER =62/15CM

MEANS:

X+X+4/3=62/15

=LETS SOLVE IT

1. 2X+4/3=62/14

• TO SEPARATE 2X JUST SHIFT 4/3TO R.H.S
• THEN EQUATION BECOMES

1. 2X=62/15-4/3

• SIMPLIFY THE LIKE TERMS

1. 2X= 62×1-4×3

15

2X=50

15

NOW SHIFT 15 TO L.H.S WITH MULTIPLY WITH 2X

• THEN, 2X×15=50
• 30X=50

1. NOW JUST TRANSFER 30 ONLY TO R.H.S

• MEANS, X=50

30

• NOW CANCEL OUT 50 AND 30
• THEREFORE X=5

3

• MEANS,MEASURE OF BOTH SIDES IS 5/3CM

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