Math, asked by sohamkumar532, 9 months ago


The base of an isosceles triangle is 4/3cm. The perimeter of the triangle is 62/15cm
What is the length of either of the remaining equal sides?

Answers

Answered by kunjmishra75
6

Answer:

Brainly.in

What is your question?

kunjmishra75

Base=4/3cm

Let the equal sides be x.

Perimeter=S1+S2+S3

62/15=x+x+4/3

62/15=2x+4/3

62/15-4/3=2x

(62-20)/15=2x

42/15/2=x

42/15×1/2=x

21/15=x

7/5=x

Thus,

Two equal sides = x = 7/5cm

Step-by-step explanation:

Pls mark me brainliest

Answered by kingshukdas420
0

Answer:

Step-by-step explanation:

(62÷15)-(4÷3)

=42÷15

LENGTH OF EACH SIDE=(42÷15)÷2

=14÷10

=1.4

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