the base of an isosceles triangle is 4/3cm.The perimeter of the triangle is 62/15cm.what is the length of either of the remaining equal sides
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Answer:
Base=4/3cm
Let the equal sides be x.
Perimeter=S1+S2+S3
62/15=x+x+4/3
62/15=2x+4/3
62/15-4/3=2x
(62-20)/15=2x
42/15/2=x
42/15×1/2=x
21/15=x
7/5=x
Thus,
Two equal sides = x = 7/5cm
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Answered by
3
Answer:
Base=4/3cm
Let the equal sides be x.
Perimeter=S1+S2+S3
62/15=x+x+4/3
62/15=2x+4/3
62/15-4/3=2x
(62-20)/15=2x
42/15/2=x
42/15×1/2=x
21/15=x
7/5=x
Thus,
Two equal sides = x = 7/5cm
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