Question

the base of an isosceles triangle is 4/3cm.the perimeter of the triangle is 4²/15cm.what is the length of either of the remaining equal sides??​

Answer 1

Answer:

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Step-by-step explanation:

So, base = 4/3cm

Perimeter = 4*2/15 = 8/15cm

So let the equal sides be x cm

So,

x+x+4/3 = 8/15cm

2x = 8/15 - 4/3

2x = 8-20/15 (By taking the lcm as 15)

2x = -12/15

x = -12/30 (By multiplying 1/2 on both the sides)

x = -2/5

So as the sides of the triangle cannot be -ve. So the length of the remaining 2 sides is 2/5cm.

Answer 2

Answer:

26/15

Step-by-step explanation:

use area of triangle formula (1/2×b×h)

u will get has 8/5

then as altitude also bisects the base so use phythagoras theorem henceforth side will come out to be 26/15 since it is Isos.triangle so other side is also 26/15.