Question

the base of an isosceles triangle is 4/3cm.the perimeter of the triangle is62/15 cm. what is the length of either of th remaing equal sides

Answer 1

let the length of other 2 side be x cm
perimeter of isosceles triangle= 2l+b
where l is the eqal.sides and b is the base
a/q
2x+ 4/3=62/15
(6x+4)/3=62/15
15(6x+4)=62×3
90x+60= 186
90x= 186-60
90x= 126
x=126/90
x= 7/5ans.

Answer 2

Answer:

14/10  

Step-by-step explanation:

The triangle is said to be isosceles if two of the sides are equal.

In the given question, base of isosceles= 4/3 cm

Perimeter of the isosceles triangle = 62/15

the length of the equal side = ?

As we know,

Perimeter of a triangle = sum of all its three sides

Perimeter of a triangle = 4/3+ x+x

62/15 = 4/3+ x+x

62/15-4/3 = 2x

taking LCM  of 15, 3

(62-20)/(15) = 2x

42/15 = 2x

14/5 = 2x

14/10 = x

Hence the length of the two other sides are 14/10 and 14/10