Question

the base of an isosceles triangle is 4/3cm the perimeter of the triangle is 62/15cm what is the length of either of the remaining equal sides

Answer 1

Let the length of the remaining sides be x
Given,
$2x + \frac{4}{3} = \frac{62}{15} \\ 2x = \frac{62}{15} - \frac{4}{3} = \frac{62 - 20}{15} = \frac{42}{15} \\ x = \frac{21}{15} = \frac{7}{5}$