Question

, the base of an isosceles triangle is 4 by 3 cm the perimeter of the triangle 42 by 15 CM

Answer 1

Since,
Your question is not clear I will find the length of the equal sides and the triangle's area.

Given,
An Icosceles triangle with base=4/3 cm
Perimeter of the triangle
To find,
(i) Length of the equal sides
(ii) Area of the triangle
ATQ,
Let, the equal sides be x cm
Then,
4/3+x+x=42/15
2x=42/15-4/3
2x=(42-20)/3
x=22/(3*2)
x=11/3
Now,
Let,
a=11/3 cm
b=11/3 cm
c=4/3 cm
Then,
By Using Herons formula:-
s=(a+b+c)/2
=(11/3+11/3+4/3)/2
=(26/3)/2
=26/6
=13/3
Now,
Area=√[s(s-a)(s-b)(s-c)]
=√[13/3(13/3-11/3)(13/3-11/3)(13/3-4/3)]
=√[13/3(2/3)(2/3)(3)]
=√13(2/3)²
=2/3√13 cm²

Hope this helps you!