the base of an isosceles triangle is 4 by 3 cm the perimeter of the triangle is 4 integer 2 by 15 cm what is the length of the either of the remaining equal sides
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Perimeter of isoceles triangle = 2a + b (where a is the length of equal sides)
4 2/15= 2a+4/3 = 62/15 = 2a+4/3
2a=42/15
a=21/15 = 7/5 cm
Therefore, length of equal sides= 7/5 cm = 1 2/5 cm
Anonymous:
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