Question

The base of an isosceles triangle is 4 cm longer than its altitude. If the base is the longest side of the triangle and the area of the triangle is 48cm2, what is the perimeter of the triangle?

Answer 1

Step-by-step explanation:

Let the altitude = x

base = (x+4) cm

area of ∆ = 1/2 x b x h

48 = 1/2 x (x+4)

96 = x^2 + 4x

x^2 + 4x -- 96 = 0

x^2 + 12x -- 8x -- 96 = 0

x(x+12) -- 8(x+12) = 0

(x-8)(x+12) = 0

x=8 , x=-12

since, side can't be negative so x=8 should be taken.