Question

The base of an isosceles triangle is 48 cm and one of its equal side is 30 cm. find the area of the triangle?

Answer 1

24× square root of 324

Answer 2

Answer:

432 square units

Step-by-step explanation:

We are given that The base of an isosceles triangle is 48 cm and one of its equal side is 30 cm.

So, Sides of triangle :

a = 48

b =30

c = 30

To calculate the area of given triangle we will use the heron's formula :

$Area = \sqrt{s(s-a)(s-b)(s-c)}$

Where $s = \frac{a+b+c}{2}$

a,b,c are the side lengths of triangle  

Now substitute the values :

$s = \frac{48+30+30}{2}$

$s =54$

$Area = \sqrt{54(54-48)(54-30)(54-30)}$

$Area =432$

Hence the area of the triangle is 432 square units