Question

the base of an isosceles triangle is 48cm and one of its equal sides is 30cm. find the area of the triangle

Answer 1

$\huge\boxed{\texttt{\fcolorbox{Red}{aqua}{Hey Mate!!!}}}$

$<b><i><font face=Copper black size=4 color=blue>$
Here is your answer

First we have to find the altitude,

So, as we know that,

Half of 48 is 24,

Altitude =
$= {30}^{2} - 24 {}^{2} \\ \\ = \sqrt{(900 - 576)} \\ \\ = \sqrt{324} \\ = 18cm$
Therefore, Altitude is 18 cm

Now, Area of triangle
$= \frac{1}{2} \times b \times a \\ \\ = \frac{1 \times 48 \times 18}{2} \\ \\ = 432 {cm}^{2}$
Therefore, Area of triangle is 432 cm^2.

$\large{\red{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\underline{\underline{\underline{Hope\:it\: helps\: you}}}}}}}}}}}}}}}$

$<marquee>$

$\huge\red{Plzzz \:mark\:me\:as \: brainliest}$