The base of an isosceles triangle is 5/8 cm the perimeter of the triangle is 3/5/12 cm. what is the length of either of the remaining equal sides
Answers
Step-by-step explanation:
Given :-
The base of an isosceles triangle is 5/8 cm the perimeter of the triangle is 3 5/12 cm.
To find :-
What is the length of either of the remaining equal sides ?
Solution :-
Let the length of the equal sides of an Isosceles triangle each be X cm
Given that
The base of an isosceles triangle = 5/8 cm
We know that
The perimeter of an Isosceles triangle
= 2a+b units
We have , a = X cm and b = 5/8 cm
Now,
Perimeter of the given Isosceles triangle
=> P = 2X + (5/8) cm
=> P = (16X+5)/8 cm
According to the given problem
The perimeter of the triangle = 3 5/12 cm
=> P = 41/12 cm
=> (16X+5)/8 = 41/12
On applying cross multiplication then
=>12(16X+5) = 41×8
=> 12(16X+5) = 328
=> 16X+5 = 328/12
=> 16X+5 = 82/3
=> 16X = (82/3)-5
=> 16X = (82-15)/3
=> 16X = 67/3
=> X = (67/3)/16
=> X = 67/(3×16)
=> X = 67/48
=> X = 1 19/48 cm
Therefore X = 67/48 cm or 1 19/48 cm
Answer:-
The equal sides of the given Isosceles triangle are 67/48 cm or 1 19/48 cm each.
Used formulae:-
→ The perimeter of an Isosceles triangle
= 2a+b units
- a = The length of the equal sides
- b = base of the triangle
Step-by-step explanation:
Base=4/3cm
Let the equal sides be x.
Perimeter-S1+S2+S3
62/15-x+x+4/3 62/15-2x+4/3
62/15-4/3=2x
(62-20)/15=2x 21/15-x
42/15/2=x
42/15x1/2=x
7/5=x
Thus,
Two equal sides = x = 7/5cm