Question

the base of an isosceles triangle is 6 cm and each of its equal side is 5 cm the height of the triangle is​

Answer 1

Step-by-step explanation:

Let the three sides of the triangle be A,B and C .

Then, draw a line from point D which is at the mid point of BC to A .

Now, you will see that ABD and ADC are two right angled triangle with their base 3cm and hypotenuse 5cm.

Now you can calculate the height using the Pythagoras theorem.

H² = P²+B² ( H= Hypotenuse, B= Base and P= Perpendicular or Height. )

5² = P²+3²

Or, 25 = P²+9

Or, 25-9 = P²

Or, √(25-9) = P

Or, √16 = P

Or, 4 cm = P

Therefore , the height of the triangle is 4 cm.

Answer 2

Answer:

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Step-by-step explanation:

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