Question

The base of an isosceles triangle is 6 cm and its perimeter is 16 cm. Length of each of the equal

sides is :​

Answer 1

Step-by-step explanation:

Let the base of the isosceles triangle be x cm.

Base of triangle = 6cm

Perimeter = 16 cm

According to the question,

x+x+6 = 16

=> 2x+6 = 16

=> 2x = 16-6

=> 2x = 10

=> x = 10/2

=> x = 5

Hence,the length of each equal side is 5cm.

Answer 2

Answer:

$\large\underline{\underline{\maltese{\red{\pmb{\sf{\: Given :-}}}}}}$

➬ Base of isosceles triangle = 6 cm

➬ Perimeter of triangle = 16 cm

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

$\large\underline{\underline{\maltese{\gray{\pmb{\sf{\: To \: Find :-}}}}}}$

➬ The length of each equal sides = ?

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

$\large\underline{\underline{\maltese{\orange{\pmb{\sf{\: Solution :-}}}}}}$

❒ Formula Used :

$\large{\blue{\bigstar}}{\underline{\boxed{\red{\sf{Perimeter{\small_{(Triangle) }} = a + b + c}}}}}$

➢Here :

➳ Perimeter = 16 cm

➳ A = Side 1 = 6 cm

➳ B = Side 2 = y

➳ C = Side 3 = y

$\qquad{━━━━━━━━━━━━━━}$

❒ Length of equal sides :

$\qquad{\leadsto{\sf{Perimeter = a + b + c}}}$

$\qquad{\leadsto{\sf{16 = 6 + y + y}}}$

$\qquad{\leadsto{\sf{16 - 6= y + y}}}$

$\qquad{\leadsto{\sf{10= 2y}}}$

$\qquad{\leadsto{\sf{ \dfrac{10}{2} = y}}}$

$\qquad{\leadsto{\sf{ \cancel\dfrac{10}{2} = y}}}$

$\large\qquad{\color{maroon}{:\twoheadrightarrow{\underline{\boxed{\sf{y = 5 \: cm}}}}}}{\pink{\bigstar}}$

$\qquad{━━━━━━━━━━━━━━}$

❒ Therefore :

❝ Length of equal sides is 5 cm. ❞

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

$\large\underline{\underline{\maltese{\pink{\pmb{\sf{\:Verification :-}}}}}}$

${:\longmapsto{\sf{ a + b + c = perimeter }}}$

${:\longmapsto{\sf{ 6 + y + y = 16 \: cm}}}$

${:\longmapsto{\sf{ 6 + 5 + 5 = 16 \: cm}}}$

${:\longmapsto{\sf{ 6 + 10 = 16 \: cm}}}$

${:\longmapsto{\sf{ 16 \: cm = 16 \: cm}}}$

${:\longmapsto\red{\underline{\sf{LHS = RHS }}}}$

Hence, Verified.

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