Question

the base of an isosceles triangle is 6 cm more than its equal sides if the perimeter of the triangle is 27 cm find the length of the three sides ?​

Answer 1

Answer:

Let the equal sides be x cm

Let the equal sides be x cmThen, the unequal side is x + 6 cm

Let the equal sides be x cmThen, the unequal side is x + 6 cmPerimeter of triangle = 36 cm

Let the equal sides be x cmThen, the unequal side is x + 6 cmPerimeter of triangle = 36 cmPerimeter of triangle = Sum of all sides

$36 = x + x + x + 6 \\ \\ \\ </p><p></p><p>36 - 6 = 3x \\ \\ </p><p></p><p>30 = 3x</p><p></p><p>\frac{30}{3} = x \\ </p><p> \\ 3</p><p>30</p><p> </p><p> =x</p><p></p><p>10 = x$

Therefore, equal sides of triangle are x = 10 cm and unequal side is x + 6 = 16 cm.

Hope it helps