Question

THE BASE OF AN ISOSCELES TRIANGLE IS 6CM AND EACH OF ITS EQUAL SIDES IS 5CM. THE HEIGHT OF THE TRIANGLE IS



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Answer 1

Answer:

H² = P²+B² ( H= Hypotenuse, B= Base and P= Perpendicular or Height. ) Therefore , the height of the triangle is 4 cm.

Answer 2

Step-by-step explanation:

draw a line perpendicular to base.

Now AD is perpendicular to BC

it will become height of isosceles triangle

BD=BC/2=6/2=3cm

apply Pythogoros theorem

${ab}^{2} = {ad}^{2} + {bd}^{2}$

${5}^{2} = {3}^{2} + {x}^{2} \\ {x}^{2} = 25 - 9 \\ {x}^{2} = 16 \\ x = 4$

height of isosceles triangle is 4 cm.

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