The base of an isosceles triangle is 8cm and each of its equal sides measures 6cm. Find the area of the triangle.
Answers
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Step-by-step explanation:
a side : 6
b : Base
A≈17.89cm²
Given : base of an isosceles triangle is 8cm and each of its equal sides measures 6cm
To Find : area of the triangle.
Solution:
Method 1 :
Draw a perpendicular on Base
perpendicular on unequal side in isosceles triangles bisect the side
8/2 = 4 cm
Apply Pythagoras theorem
6² - 4² = h²
=> 36 - 16 = h²
=> 20 = h²
=> 2√5 = h
Area of Triangle = (1/2) bh
= (1/2) * 8 * 2√5
= 8 √5 cm²
Method 2:
Using Heron Formula
s = (6 + 6 + 8)/2 = 10
Area = √(10(10 - 6)(10 -6)(10-8))
=√(10(4)(4)(2))
=√( 2*5)(4)(4)(2))
= √( 2²*5)(4²)
= 2 * 4 √5
= 8√5 cm²
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