The base of an isosceles triangle is x cm long. Each of the other sides is 4 cm longer than the base. The perimeter of the triangle is 24.5 cm. Form an equation with x and solve it to find the length of the base.
Answers
Step-by-step explanation:
Let x be length of equal sides of isoscles triangle & y be length of base
Perimeter = 2x+y
2x+y=62
Given [x=y+4]
2(y+4)+y=62
3y=62-8
3y=54
[y=18 cm] and x= y+4=22 cm
∴ length of equal side is 22 cm & length of base is 18 cm.
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Answer:
Let the side of an isosceles triangle be x cm since opposite sides of an isosceles triangle are equal. So another side =xcm
Let the side of an isosceles triangle be x cm since opposite sides of an isosceles triangle are equal. So another side =xcmAs given the base side is 3cm more then the other side.
Let the side of an isosceles triangle be x cm since opposite sides of an isosceles triangle are equal. So another side =xcmAs given the base side is 3cm more then the other side.So base side =x+3cm
Let the side of an isosceles triangle be x cm since opposite sides of an isosceles triangle are equal. So another side =xcmAs given the base side is 3cm more then the other side.So base side =x+3cm⇒ Perimeter of a triangle = sum of all sides
Let the side of an isosceles triangle be x cm since opposite sides of an isosceles triangle are equal. So another side =xcmAs given the base side is 3cm more then the other side.So base side =x+3cm⇒ Perimeter of a triangle = sum of all sides ⇒54=x+x+x+3
Let the side of an isosceles triangle be x cm since opposite sides of an isosceles triangle are equal. So another side =xcmAs given the base side is 3cm more then the other side.So base side =x+3cm⇒ Perimeter of a triangle = sum of all sides ⇒54=x+x+x+3 54=3x+3
Let the side of an isosceles triangle be x cm since opposite sides of an isosceles triangle are equal. So another side =xcmAs given the base side is 3cm more then the other side.So base side =x+3cm⇒ Perimeter of a triangle = sum of all sides ⇒54=x+x+x+3 54=3x+3 54−3=3x
Let the side of an isosceles triangle be x cm since opposite sides of an isosceles triangle are equal. So another side =xcmAs given the base side is 3cm more then the other side.So base side =x+3cm⇒ Perimeter of a triangle = sum of all sides ⇒54=x+x+x+3 54=3x+3 54−3=3x 51=3x
Let the side of an isosceles triangle be x cm since opposite sides of an isosceles triangle are equal. So another side =xcmAs given the base side is 3cm more then the other side.So base side =x+3cm⇒ Perimeter of a triangle = sum of all sides ⇒54=x+x+x+3 54=3x+3 54−3=3x 51=3x x=351
Let the side of an isosceles triangle be x cm since opposite sides of an isosceles triangle are equal. So another side =xcmAs given the base side is 3cm more then the other side.So base side =x+3cm⇒ Perimeter of a triangle = sum of all sides ⇒54=x+x+x+3 54=3x+3 54−3=3x 51=3x x=351⇒x=17
Let the side of an isosceles triangle be x cm since opposite sides of an isosceles triangle are equal. So another side =xcmAs given the base side is 3cm more then the other side.So base side =x+3cm⇒ Perimeter of a triangle = sum of all sides ⇒54=x+x+x+3 54=3x+3 54−3=3x 51=3x x=351⇒x=17So the sides of triangle are 17cm and the base side of triangle 20cm.
Let the side of an isosceles triangle be x cm since opposite sides of an isosceles triangle are equal. So another side =xcmAs given the base side is 3cm more then the other side.So base side =x+3cm⇒ Perimeter of a triangle = sum of all sides ⇒54=x+x+x+3 54=3x+3 54−3=3x 51=3x x=351⇒x=17So the sides of triangle are 17cm and the base side of triangle 20cm.Hence, solved.