Question

The base of an isosceles triangle is4/3cm.The perimeter of the triangle is62/15cm.What is the length of the remaining equal sides?​

Answer 1

Answer:21/15 cm

Step-by-step explanation:-

Let us take one of the unknown side as x

The base of the isosceles triangle=4/3 cm= 20/15 cm [By LCM method]

The perimeter of the triangle= 62/15cm

So, the sum of the two other sides of the triangle are= 62/15 cm - 20/15 cm

= 42/15 cm

If this is an isosceles triangle then,

2x= 42/15 cm

Therefore, x= 42/15 cm divided by 2= 21/15 cm=7/5cm

Answer 2

Step-by-step explanation:

$permiter \: of \: isosceles \: = 2 \: equal \: side \: + \: base \: \\ \\ \frac{62}{15} = 2(ab ) + bc \\ \frac{62}{15} = 2(ab) + \frac{4}{3} \\ \frac{62}{15} - \frac{4}{3} = 2(ab) \\ \frac{62 - 20 }{15} = 2(ab) \\ \frac{40}{15} = 2(ab) \\ \frac{40}{15} \times \frac{1}{2} = ab \\ ab = \frac{20}{15 } \\ ab = \frac{5 \times 4}{5 \times 3} = \frac{4}{3} \\ equa \: side \: of \: isosceles \: triange \: is \:$