The base of an isosceles triangle measure 24cm and its area is 60cm find its perimeter
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Area of an isosceles triangle =1/2×base×height
Here , Base=24cm
Area of isosceles triangle =
1/2 × 24 × height =60
So,12 h= 60
Hence , h = 60/12 = 5cm
Now height=5cm
base=24cm
So , hypotenuse = ?
We know by Pythagoras theorem that (AB)²+(BC)²= (AC)²
Here
a = 24/2=12cm (As base is divided into two parts by the altitude)
b=5cm
So,
(hypotenuse)² = (12)² + (5)² =169 cm
So , side = hypotenuse = √169 =13cm
So ,
Perimeter = 24 cm +13 cm +13 cm = 50 cm
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