Question

the base of an isosceles triangle measure 80 cm and its area is 360 CM square find the perimeter of the triangle​

Answer 1

Answer:

ANSWER

Area of triangle =21×base×height=360 sq cm

21×80×height=360

=> height =9 cm.

Since the height of the triangle, divides it into two right angled triangles,

a2=h2+(2b)2=>a2=92+(280)2=1681

Hence, a=41 cm. 

Perimeter of the triangle = Sum of all sides = a + a + b =41+41+80=162cm