Question

The base of an isosceles triangle measure 80cm and it's area is 360cm² . Find the perimeter of triangle

Answer 1

Answer:

A=bhb

2

P=2a+b

hb=a2﹣b2

4

Solving forP

P=b+b2+16(A

b)2=80+802+16·(360

80)2=162cm

Step-by-step explanation:

answer 162 cm²

Answer 2

Step-by-step explanation:

Area of triangle=1/2×b×h. 360=1/2×80×h. 360=80/2×h. 360=40×h. 360/40=h. h=9. Since the hight of the triangle divides it into right angle triangle. a^2=h^2+(b/2)^2. = a^2=9^2+(80/2)^2. a^2=81+6400/4. =a^2=81+1600. a^2=1681. = a = √1681=√41×41. a=41cm. perimeter of the triangle =sum of all sides. a+a+b=41+41+80=162 cm^2.