the base of an isosceles triangle measure 80cm and its area is 360cm^2.find the perimeter of the triangle
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Hi,
here's your answer.......................…........………!
let the equal sides of the an isosceles triangle be X
so, X+X+80=180(angle sum property of triangle)
2x+80=180
2x=180-80=100
X=100/2
X=50
PERIMETER OF AN ISOSCELES TRIANGLE:
X+X+80
=50+50+80
=180
hence, perimeter = 180cm
here's your answer.......................…........………!
let the equal sides of the an isosceles triangle be X
so, X+X+80=180(angle sum property of triangle)
2x+80=180
2x=180-80=100
X=100/2
X=50
PERIMETER OF AN ISOSCELES TRIANGLE:
X+X+80
=50+50+80
=180
hence, perimeter = 180cm
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