Question

the base of an isosceles triangle measures 24 cm and its perimeter is 64 cm find its area ​

Answer 1

Answer:

the answers of this question is that 192cm²

Answer 2

${\tt{\underline{Given :-}}}$

The base of an isosceles triangle measures 24 cm and its perimeter is 64 cm

${\tt{\underline{Need\;to\;find:-}}}$

area of the given triangle

${\tt{\underline{Answer :-}}}$

Here, it is given an isosceles triangle which has a base of 24 cm. Two sides of an isosceles triangle areequal

Let the equal sides be a

The Perimeter of triangle = Sum of all sides

=> 64 = 24 + a + a

=> 64 = 24 + 2a

=> 64 - 24 = 2a

=> 40 = 2a

=> 40 ÷ 2 = a

=> 20 = a

Area by using heron's formulae

=> Semiperimeter = 1/2 × (a + b + c)

=> Semiperimeter = 1/2 × 64

=> Semiperimeter = 32 cm

=> Area = √s(s-a)(s-b)(s-c)

=> Area = √32(32-24)(32-20)(32-20)

=> Area = √32(8)(12)(12)

=> Area = 12√32(8)

=> Area = 12√(256)

=> Area = 12 × 16

=> Area = 192 sq. cm

Hope it helps you buddy!