Question

The base of an isosceles triangle measures 24cm and its area is 60cm^2 find its perimeter

Answer 1

↑ Here is your answer ↓
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Area of a triangle,

$= 1/2 * b * h$

$1/2 * 24 * h = 60$

$12 * h = 60$

$h = 60/12$

$h = 5cm$

We know that,

Altitude of an isosceles triangle divides it into two congruent triangles,

Take one of those triangles,

Let the hypotenuse be 'y',

$y^2 = 5^2 + 12^2$

$y^2 = 25 + 144$

$y^2 = 169$

$y = 13 cm$

Now lets add all the sides,

$= 24 + 13 + 13$

$= 50cm$