The base of an isosceles triangle measures 24cm and its area is 60cm find its perimeter
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Hey mate...
Here's ur answer...
Given =>
➡Base of isosceles ∆=24 cm
➡Perimeter = 60 cm
➡Let the non- given equal sides be 'x'
▶Perimeter of a ∆ = a + b + c
▶60 cm = 24cm + x + x
▶60cm = 24cm + 2x
▶60cm-24cm = 2x
▶36cm = 2x
▶36cm÷2 = x
▶18cm = x
HOPE IT HELPS U...✌✌
❤❤
Here's ur answer...
Given =>
➡Base of isosceles ∆=24 cm
➡Perimeter = 60 cm
➡Let the non- given equal sides be 'x'
▶Perimeter of a ∆ = a + b + c
▶60 cm = 24cm + x + x
▶60cm = 24cm + 2x
▶60cm-24cm = 2x
▶36cm = 2x
▶36cm÷2 = x
▶18cm = x
HOPE IT HELPS U...✌✌
❤❤
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