Question

The base of an isosceles triangles is (5/3) cm. The perimeter of the triangle 3(4/5) cm. What is the

length of either of the remaining equal sides?
please answer fast and I will mark as branlilist​

Answer 1

Question

• The base of an isosceles triangles is (5/3) cm. The perimeter of the triangle 3(4/5) cm. What is the length of either of the remaining equal sides?

Answer

• Length of remaining equal sides is 16/15 cm.

Explanation

Given that

• Base of an isosceles ∆ is 5/3 cm.
• Perimeter of an isosceles ∆ is 3(4/5) cm.

To Find

• Length of remaining equal sides?

Solution

• Converting perimeter of ∆ from mixed fraction to simple fraction,

↦ Perimeter of ∆ = $\sf 3\dfrac{4}{5}$

↦ Perimeter of ∆ = $\sf \dfrac{\big(3\:\times\:5\big) + 4}{5}$

↦ Perimeter of ∆ = $\sf \dfrac{15 + 4}{5}$

➡ Perimeter of ∆ = $\pmb{\boxed{\bf{\red{\dfrac{19}{5}\:cm^2}}}}$

Now,

• Let equal sides be x
• Using formula of perimeter,

We know that,

⇒ Perimeter of ∆ = Sum of all sides

Putting all values,

⇒ $\sf \dfrac{19}{5} = \dfrac{5}{3} + x + x$

⇒ $\sf \dfrac{19}{5} - \dfrac{5}{3} = 2x$

⇒ $\sf \dfrac{57}{15} - \dfrac{25}{15} = 2x$

⇒ $\sf \dfrac{57 - 25}{15} = 2x$

⇒ $\sf \dfrac{32}{15} = 2x$

⇒ $\sf \dfrac{32}{15\:\times\:2} = x$

⇒ $\sf x = {\cancel{\dfrac{32}{30}}}$

➦ x = $\pmb{\boxed{\bf{\purple{\dfrac{16}{15}\:cm}}}}$

$\:$

• Therefore, length of remaining equal sides is 16/15 cm.

Know More

• Perimeter of rectangle = 2(ℓ + b)
• Perimeter of square = 4 × side
• Perimeter of circle = 2πr
• Perimeter of equilateral ∆ = 3 × side

━━━━━━━━━━━━━━━━━━━━━━━━━

Answer 2

Answer:

$\underline{\purple{\ddot{\Maths dude}}}$

◇◇Given:-

• The base of an issoceles triangles is 5/3 cm.
• The perimeter of triangles is 3(4/5)cm

◇◇To prove :-

• The length of either of remaining equal sides .

◇◇Proof:-

• Now ,
• Let , the either remaining equal sides be x .

1. We know that,

• Perimeter = sum of all equal sides.

♧♧Now applying the values,

☆we get,

• 3×4/5 = 5/3+x+x
• 12/5 = 5/3+2x
• 12/5-5/3= 2x
• 57 -25/15 = 2x
• 32 /15 =2x
• 32/15×2 =2x
• x = 32/30
• x = 16/15cm

♤♤Therefore,

• The lenght of either of remaining equal sides is 16/15cm

♧♧Hope it helps u mate.

♧♧Thank you .