The base of an isoscelless triangle is 12 cm and its perimeter is 32 cm. then find its area?
Answers
Answered by
0
let the both equal sides be x.
x+x+12= 32
area you can find by heron's formula
Answered by
1
Two sides of an isosceles triange are equal. Consider them x.
X+x+12=32 (perimeter)
2x=32-12
2x=20
X=10
Length of two sides=10cm
Area=a/4*root4bsquare-asquare
The final answer 620 cm square.
X+x+12=32 (perimeter)
2x=32-12
2x=20
X=10
Length of two sides=10cm
Area=a/4*root4bsquare-asquare
The final answer 620 cm square.
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