Question

the base of an isoscles traingle is 16 cm if its perimeter is 36 cm find its area​

Answer 1

Step-by-step explanation:

let the two equal sides be x cm

ATP

x+ x+16=36

2x +16=36

2x = 36-16

2x= 20

x= 10

so the two sides are 10 cm

now semiperimeter (s) = 36÷2 =18

area :√(s-a)(s-b)(s-c) cm^2

√18(18-10)(18-10)(18-16) cm^2

√18× 8×8×2 cm^2

3×8×2 cm^2

48 cm^2 (ans)

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Answer 2

96.64 cm²

Step-by-step explanation:

perimeter = 36

sides of triangle be a,b,c where a,b are isoscles sides which are equal and other side that is base side c = 16cm.

therefore a+b+c = 36

a = b ⇒ a+a+16 = 36

therfore 2a + 16 = 36

a = (36 - 16) ÷ 2

a = 10 cm

and since a = b ⇒ b = 10cm

area of the triangle

consider a perpendicular line from vertex of side a and side b and draw a mid line to the base c which divides the base line into two equal halves.

therefore height h = √a² + (c÷2)²

therefore √10² + (16 ÷ 2)²

h = 12.80 cm

area = 0.5 × base ×height

area = 0.5 × 16 × 12.08

= 96.64 cm²