the base of an isoscles traingle is 16 cm if its perimeter is 36 cm find its area
Answers
Step-by-step explanation:
let the two equal sides be x cm
ATP
x+ x+16=36
2x +16=36
2x = 36-16
2x= 20
x= 10
so the two sides are 10 cm
now semiperimeter (s) = 36÷2 =18
area :√(s-a)(s-b)(s-c) cm^2
√18(18-10)(18-10)(18-16) cm^2
√18× 8×8×2 cm^2
3×8×2 cm^2
48 cm^2 (ans)
here your answer mark me the brainliest
96.64 cm²
Step-by-step explanation:
perimeter = 36
sides of triangle be a,b,c where a,b are isoscles sides which are equal and other side that is base side c = 16cm.
therefore a+b+c = 36
a = b ⇒ a+a+16 = 36
therfore 2a + 16 = 36
a = (36 - 16) ÷ 2
a = 10 cm
and since a = b ⇒ b = 10cm
area of the triangle
consider a perpendicular line from vertex of side a and side b and draw a mid line to the base c which divides the base line into two equal halves.
therefore height h = √a² + (c÷2)²
therefore √10² + (16 ÷ 2)²
h = 12.80 cm
area = 0.5 × base ×height
area = 0.5 × 16 × 12.08
= 96.64 cm²