The base of an isosoceles triangle is 24cm and its area is 192sq.cm.Find the perimeter
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Area=(base×height)/2
192=(24×h)/2
192=12h
h=192/12=16cm. , let length of each equal side=x cm.
using Pythagoras formula:-
h^2+(base/2)^2=x^2
16^2+12^2=x^2
256+144=x^2
400=x^2
x=20 cm.
Perimeter=20+20+24=64
192=(24×h)/2
192=12h
h=192/12=16cm. , let length of each equal side=x cm.
using Pythagoras formula:-
h^2+(base/2)^2=x^2
16^2+12^2=x^2
256+144=x^2
400=x^2
x=20 cm.
Perimeter=20+20+24=64
aryakrish:
well
that answer is correct
thanku
can u explain it briefly
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