Question

the base of an usos eles triangle is 4/5 cm the perimeter of the triangle is 5 integer 3/5 cm what is the length of either of the remaining equal sides​

Answer 1

Answer:

area=1/2*b*h

60=1/2*13*h      (where h=height of the Δ)

60*2*1/13=h

120/13=h

9.23=h

thus height of the triangle=9.23cm

Step-by-step explanation:

mate here your answer

Answer 2

Answer:

Step-by-step explanation:

Let the length of equal sides be x cm.

Perimeter = x cm + x cm + Base = 4 2/15 cm 2x + 4/3 = 62/15

On transposing 4/3 to R.H.S, we obtain 2x = 62/15 - 4/3 2x = 62 - 4 x 5/15 = 62 - 20/15 2x = 42/15

On dividing both sides by 2, we obtain 2x/2 = 42/15 x1/2 x = 7/5 = 1 2/5

Therefore, the length of equal sides is 1 2/5 c m.

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